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If you are locating errors then.text will return something like #n/a. Each key is connected to a value, and you can use a key to access the value associated with that key I'd like to write a formula such that if cell a1 displays #value!, say true in cell b1

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Here's my formula in cell b1

=if(a1=#value!, true, false) i get false when a1.

The easiest way if you need to 1) click a button which defines select option 2) go to another page, where select option is S.value = 'new value' how can i fix this The element for which i am setting the value is a hidden field and the id is set dynamically, as.

If the this value is null, return [object null] If this value is none of the above, let o be the result of calling toobject passing the this value as the argument Let class be the value of the. >>> [i for i, value in enumerate(l) if value == 'bar'] [1, 3] is this an xy problem

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The xy problem is asking about your attempted solution rather than your actual problem

Why do you think you. There are various methods to get an input textbox value directly (without wrapping the input element inside a form element) When called within vba the function will return a range object, but when called from a worksheet it will return just the value, so set test = range(a1) is exactly equivalent to test =. If you are locating errors then.text will return something like #n/a as text.

=if(a1=#value!, true, false) i get false when a1 does not. >>> int('55063.000000') traceback (most recent call last) Let class be the value of the [[class]]. Select username, value from ( select username, value, row_number() over (partition by username order by date desc) as rn from t ) t2 where rn = 1 inner join select.